How to generate or list all possible permutations in Excel?

For example, I have three characters XYZ, now, I want to list all possible permutations based on these three characters to get six different results as this: XYZ, XZY, YXZ, YZX, ZXY and ZYX. In Excel, how could you quickly generate or list all permutations based on different number of characters?

Generate or list all possible permutations based on characters with VBA code

Generate or list all possible permutations based on characters with VBA code

The following VBA code may help you to list all permutations based on your specific number of letters please do as follows:

1. Hold down the ALT + F11 keys to open the Microsoft Visual Basic for Applications window.

2. Click Insert > Module, and paste the following code in the Module Window.

VBA code: List all possible permutations in excel

``````Sub GetString()
'Updateby Extendoffice
Dim xStr As String
Dim FRow As Long
Dim xScreen As Boolean
xScreen = Application.ScreenUpdating
Application.ScreenUpdating = False
xStr = Application.InputBox("Enter text to permute:", "Kutools for Excel", , , , , , 2)
If Len(xStr) < 2 Then Exit Sub
If Len(xStr) >= 8 Then
MsgBox "Too many permutations!", vbInformation, "Kutools for Excel"
Exit Sub
Else
ActiveSheet.Columns(1).Clear
FRow = 1
Call GetPermutation("", xStr, FRow)
End If
Application.ScreenUpdating = xScreen
End Sub
Sub GetPermutation(Str1 As String, Str2 As String, ByRef xRow As Long)
Dim i As Integer, xLen As Integer
xLen = Len(Str2)
If xLen < 2 Then
Range("A" & xRow) = Str1 & Str2
xRow = xRow + 1
Else
For i = 1 To xLen
Call GetPermutation(Str1 + Mid(Str2, i, 1), Left(Str2, i - 1) + Right(Str2, xLen - i), xRow)
Next
End If
End Sub
``````

3. Then press F5 key to run this code, and a prompt box is popped out to remind you enter the characters that you want to list all permutations, see screenshot:

4. After entering the characters, and then click OK button, all the possible permutations are displayed in column A of active worksheet. See screenshot:

Note: If the entered character length is equal or greater than 8 characters, this code will not work because there are too many permutations.

List or generate all possible combinations from multiple columns

If you need to generate all possible combinations based on multiple columns data, maybe, there is not a good way for dealing with the task. But, Kutools for Excel's List All Combinations utility can help you to list all possible combinations quickly and easily. Click to download Kutools for Excel!

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This comment was minimized by the moderator on the site
OlÃ¡ !

Como faÃ§o para gerar pelo menos 10 permutaÃ§Ãµes ?
This comment was minimized by the moderator on the site
Hello, Mateus,
To solve your problem, please apply the below code:(Note: if there are more than 8 characters, the code will execute slowly.)
``````Sub GetString()
'Updateby Extendoffice
Dim xStr As String
Dim FRow As Long
Dim FC As Integer
Dim xScreen As Boolean
Dim xNumber As Long
xNumber = 10 ' This is the max length of the characters you can change it to 11, 12, 13...as you need
xScreen = Application.ScreenUpdating
Application.ScreenUpdating = False
xStr = Application.InputBox("Enter text to permute:", "Kutools for Excel", , , , , , 2)
If Len(xStr) < 2 Then Exit Sub
If Len(xStr) > xNumber Then
MsgBox "Too many permutations!", vbInformation, "Kutools for Excel"
Exit Sub
Else
ActiveSheet.Columns(1).Clear
FRow = 1
FC = 1
Call GetPermutation("", xStr, FRow, FC)
End If
Application.ScreenUpdating = xScreen
End Sub
Sub GetPermutation(Str1 As String, Str2 As String, ByRef xRow As Long, ByRef xc As Integer)
Dim i As Integer, xLen As Integer
xLen = Len(Str2)
If xLen < 2 Then
If xRow > 1000000 Then
xc = xc + 1
xRow = 1
End If
ActiveSheet.Cells(xRow, xc) = Str1 & Str2
xRow = xRow + 1
Else
For i = 1 To xLen
Call GetPermutation(Str1 + Mid(Str2, i, 1), Left(Str2, i - 1) + Right(Str2, xLen - i), xRow, xc)
Next
End If
End Sub``````

This comment was minimized by the moderator on the site
Hi there, if the input string contains duplicate chars, then the sub produces duplicate permutations.
This does not happen if you make the following modification the the loop:

' ==========================
For i = 1 To xLen
If Instr( Left(Str2, i - 1), Mid(Str2, i, 1) ) = 0 then
Call GetPermutation(Str1 + Mid(Str2, i, 1), Left(Str2, i - 1) + Right(Str2, xLen - i), xRow)
End if
Next
' ==========================

Creating temporary local variables for Mid(Str2, i, 1) and for Left(Str2, i - 1), and avoiding the test for i=1 makes it go faster:

' ==========================
Sub GetPermutation(Str1 As String, Str2 As String, ByRef xRow As Long)
Dim i As Integer, xLen As Integer, Str2left as String, c as String
xLen = Len(Str2)
If xLen < 2 Then
Range("A" & xRow) = Str1 & Str2
xRow = xRow + 1
Else
Call GetPermutation(Str1 + Mid(Str2, 1, 1), Right(Str2, xLen - 1), xRow)
For i = 2 To xLen
c = Mid(Str2, i, 1)
Str2left = Left(Str2, i - 1)
If Instr( Str2left, c ) = 0 then
Call GetPermutation(Str1 + c, Str2left + Right(Str2, xLen - i), xRow)
End If
Next
End If
End Sub
' ==========================

Cheers,
DVdm
This comment was minimized by the moderator on the site
who can send me a list of 10 diferent items permutatted by 2 outcomes. this code doe

snt work on this
This comment was minimized by the moderator on the site
peki bunu listeleyecek bir program uygulama yok mu?basit sÄ±radan bir hesaplamadan daha fazlasÄ±na ihtiyacÄ± olan ne yapacak?
This comment was minimized by the moderator on the site
this code will not work because there are two many permutations

should be:

this code will not work because there are too many permutations

HTH
This comment was minimized by the moderator on the site
Hello, MC,
Thank you for your warm reminder, it is my mistake. I have corrected it.
Thanks a lot!
This comment was minimized by the moderator on the site
Hello everyone. I need help on this. I have two alphabets to be permutated in 20 rows. But am not getting it right. Anyone who could help me out should send the permutation to my email. .

1.a b b a
2.a a b b
3.a a b b
4.a a b b
5.a a b b
6.a a b b
7.a a b b
8.a a b b
9.a a b b
10.a a b b
11.a a b b
12.a a b b
13.a a b b
14.a a b b
15.a a b b
16.a a b b
17.a a b b
18.a a b b
19.a a b b
20.a a b b
This comment was minimized by the moderator on the site
How many sequences of 3things can be formed from 7 different things replacement and order is important?
This comment was minimized by the moderator on the site
3 to the power of 7: 2187
This comment was minimized by the moderator on the site
@Supraja...

in the first sub clear all cells... not just the first row
--Cells.Clear

Sub GetPermutation(Str1 As String, Str2 As String, ByRef xRow As Long)
Dim i As Integer, xLen As Integer
xLen = Len(Str2)
If xLen < 2 Then
'move to the next column when you get to 100
Cells(((xRow - 1) Mod 100) + 1, 1 + Int(xRow / 100)) = Str1 & Str2
xRow = xRow + 1
Else
For i = 1 To xLen
Call GetPermutation(Str1 + Mid(Str2, i, 1), Left(Str2, i - 1) + Right(Str2, xLen - i), xRow)
Next
End If
End Sub
This comment was minimized by the moderator on the site
Hello,

Im trying to get a permutation for 82 characters, the code provided works, but, since the columns are only 1048576, I want to move the next output in B,C,D..... Can any of you help me on this regard
This comment was minimized by the moderator on the site
Hello, Im doing a small project using permutation and combination rules. I need your support on this please. Scenario: I have 13 digit alpha numeric data (00SHGO8BJIDG0) I want a coding to interchange S to 5, I to 1 and O to 0 and vise versa. The project is that if I have the correct 13 digit data I will receive a 3 digit pass code. (eg) 00SHG08BJ1DG0 - 500 is the pass code but because of wrong typo that is instead of 1 it was I and 0 it was O there is a wrong info. can you please help me.
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