How to list all matched instances of a value in Excel?
As the left screenshot shown, you need to find and list all match instances of value “Linda” in the table. How to achieve it? Please try the methods in this article.
With the following array formula, you can easily list all match instances of a value in a certain table in Excel. Please do as follows.
1. Select a blank cell to output the first matched instance, enter the below formula into it, and then press the Ctrl + Shift + Enter keys simultaneously.
Note: In the formula, B2:B11 is the range which the matched instances locate in. A2:A11 is the range contains the certain value you will list all instances based on. And D2 contains the certain value.
2. Keep selecting the result cell, then drag the Fill Handle down to get the other matched instances.
You can easily find and list the first matched instance of a value with the Look for a value in list function of Kutools for Excel without remembering formulas. Please do as follows.
Before applying Kutools for Excel, please download and install it firstly.
1. Select a blank cell you will place the first matched instance, then click Kutools > Formula Helper > Formula Helper.
2. In the Formulas Helper dialog box, you need to:
Tips: You can check the Filter box, enter the keyword into the textbox to quickly filter the formula you need.
Tips: The column number is based on the selected number of columns, if you select four columns, and this is the 3rd column, you need to enter number 3 into the Column box.
Then the first matched instance of the given value is listed as below screenshot shown.
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- To post as a guest, your comment is unpublished.· 3 days agoQuestion, I have a sheet laid out opposite of this where "Linda" would be the column header I would like to flag on and the value "90" or 89" I would like to return. Would I change the row function to a column function?
- To post as a guest, your comment is unpublished.· 1 months agoHow would I use this formula but instead of filling down I could fill across but the formula would continue moving down as I fill across (ie. the formula changes from ROW(1:1) to ROW(2:2)
- To post as a guest, your comment is unpublished.· 21 days agoHi Luke,The below array formula can do you a favor.Note: After entering the formula, please press the Ctrl + Shift + Enter key to apply it. And then drag its Fill Handle right across the cells you need.=INDEX($B$2:$B$11, SMALL(IF($D$2=$A$2:$A$11, ROW($A$2:$A$11)-ROW($A$2)+1), COLUMN(A1)))
- To post as a guest, your comment is unpublished.· 1 years agoA very useful and educational formula. I am matching against a set numeric value and it works a treat. How can I use >= rather than just = (i.e. IF($D$2>=$A$2:$A$11) to perform the match so it is looking for values greater than a set value (in $D$2). I assume as it doesn't work as one of the functions in the formula is matching against specific text rather than working with numbers?
- To post as a guest, your comment is unpublished.· 1 years agoThis was super useful, thanks! I'm trying to take this one step further and be able to return all match instances of a certain value while having to search through more than a single-column array. To work through this using your example, I added a second column of test scores and modified your formula to look up a given test score and return the names that match that score. I got this to work with INDEX(SMALL()) and can pull all of the names from both test columns. I've also managed to return only names with that score on Test 2 using INDEX(MATCH(INDEX(MATCH))), however this can only find the first instance in the array. What I'm really trying to do is a combination of these: return all of the names with the given array, while narrowing the search to a specific column within the array. Do you have any tips for this?
- To post as a guest, your comment is unpublished.· 1 years agoGood day,
Would you please provide a screenshot of your spreadsheet showing what you are exactly trying to do? Thank you for your comment.
- To post as a guest, your comment is unpublished.· 3 years agoIs there a similar formula that will work in google sheets?