How to rank values by group in Excel?
In this article, I will talk about ranking values by group in Excel as below screenshot shown.
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There is a formula to quickly rank values based on group.
Select a blank cell next to the data, C2 for instance, type this formula, =SUMPRODUCT(($A$2:$A$11=A2)*(B2<$B$2:$B$11))+1 then drag autofill handle down to apply this formula to the cells you need.
In the formula, A2:A11 is the range containing the group values, A2 is the first cell in the list of group values, B2 is the first cell in the list which needed to rank, B2:B11 is the list that contains values needed to rank.
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- To post as a guest, your comment is unpublished.· 4 months agohi sunny, i have a complex query here but need to visualize it to better understanding. how can i contact u with visualization?v
- To post as a guest, your comment is unpublished.· 8 months agoHow can I get it to rank in reverse order, from smallest to largest?
- To post as a guest, your comment is unpublished.· 5 months agoHi, Brian Q, you can use this formula =SUMPRODUCT(($A$2:$A$11=A2)*(B2<$B$2:$B$11))+1 to ranke from smallest to largest
- To post as a guest, your comment is unpublished.· 2 months agoI'm sorry, but I don't see a difference between this formula and the one above.
- To post as a guest, your comment is unpublished.· 29 days agoB2> ; just reverse from less than to greater than.
- To post as a guest, your comment is unpublished.· 2 years agoThis is EXCEL-lent (see what I did there?)! Now that you have the rankings by group, how do you find out % from #1 rank within the group? For example, Group A has record 100 as #1, and record 93 as #3 ranked. If I wanted to add another column to find out how far off in percentage record #3 (93) is from record #1 (100), what is the formula to achieve this? The result should be rank #1 is 0%, and rank #3 is 7% off ((100/93)-1) from rank #1
- To post as a guest, your comment is unpublished.· 1 years agoDevide the subject by the max of the group using a max if.
- To post as a guest, your comment is unpublished.· 2 years agoSorry I have not found a formula or other solution can handle ur question.