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 How to create a dependent drop down list in Google sheet?

Inserting normal drop down list in Google sheet may be an easy job for you, but, sometimes, you may need to insert a dependent drop down list which means the second drop down list depending on the choice of the first drop down list. How could you deal with this task in Google sheet?

Create a dependent drop down list in Google sheet


Create a dependent drop down list in Google sheet


The following steps may help you to insert a dependent drop down list, please do as this:

1. First, you should insert the basic drop down list, please select a cell where you want to put the first drop down list, and then click Data > Data validation, see screenshot:

2. In the popped out Data validation dialog box, select List from a range from the drop down list beside the Criteria section, and then click button to select the cell values which you want to create the first drop down list based on, see screenshot:

3. Then click Save button, the first drop down list has been created. Choose one item from the created drop down list, and then enter this formula: =arrayformula(if(F1=A1,A2:A7,if(F1=B1,B2:B6,if(F1=C1,C2:C7,"")))) into a blank cell which adjacent the data columns, then press Enter key, all the matching values based on the first drop down list item have been displayed at once, see screenshot:

Note: In the above formula: F1 is the first drop down list cell, A1, B1 and C1 are the items of the first drop down list, A2:A7, B2:B6 and C2:C7 are the cell values which the second drop down list based on. You can change them to your own.

4. And then you can create the second dependent drop down list, click a cell where you want to put the second drop down list, and then click Data > Data validation to go to the Data validation dialog box, choose List from a range from the drop down beside the Criteria section, and go on clicking the button to select the formula cells which are the matching results of the first drop down item, see screenshot:

5. At last, click Save button, and the second dependent drop down list has been created successfully as the following screenshot shown:


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  • To post as a guest, your comment is unpublished.
    Guest · 2 months ago
    Now is needed to use: =arrayformula(if(F1=A1;A2:A7;if(F1=B1;B2:B6;if(F1=C1;C2:C7;""))))
  • To post as a guest, your comment is unpublished.
    Nick · 3 months ago
    Hi,
    I was wondering if anyone could advise me with this? I've followed the above steps but on step 3 rather than getting:
    "...all the matching values based on the first drop down list item have been displayed at once," I am just seeing one value (the top one from the drop down list).
    My cells are placed slightly differently and the first drop down is filled from another sheet (from anywhere int eh column excluding the top row) so my formula is:

    =arrayformula(if(VLE!D2:D=B11,B12,if(VLE!D2:D=C11,C12:C14,if(VLE!D2:D=D11,D12:D14,if(VLE!D2:D=E11,E12:E16,if(VLE!D2:D=F11,F12:F16,""))))))

    It is correctly displaying the top drop down option for each of (using cell numbers from the step 3 example on this page) A1, B1, and C1 so, again using this page's example, if I select Asia form the F1 drop down, I would get China, but nothing further


    Any suggestions?

    Many thanks! Nick
  • To post as a guest, your comment is unpublished.
    Andrew · 5 months ago
    If the first drop own is on sheet 1 A1, will this work were I want the second drop down as sheet 1 A2, but to have its data range on a separate sheet?
  • To post as a guest, your comment is unpublished.
    Peter · 6 months ago
    Ich bekomm immer die Meldung "Fehler beim Parsen der Formel" wenn ich =arrayformula(if(F1=A1,A2:A7,if(F1=B1,B2:B6,if(F1=C1,C2:C7,"")))) eingebe. Was ist der "Weiter-Schlüsel"? Reicht es nicht wie bei Excel die Formel einzugeben?
    • To post as a guest, your comment is unpublished.
      Geyza · 3 months ago
      Ersetzen Sie den , zu ;
      es hat für mich funktioniert
  • To post as a guest, your comment is unpublished.
    Alexis · 10 months ago
    This is the best explanation I have found, so thank you for that!

    In my situation, I am working with over 200 rows with more being continuously added. Is there an easier/more efficient way to handle this many rows?
    • To post as a guest, your comment is unpublished.
      Lad · 7 months ago
      Yes, if you don't put number index to specify ending cell.
      Like instead of C2:C7 you put C2:C. This will automatically tell the array formula, that you want to consider all values in column "C" starting at "C2".