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How to extract date from text strings in Excel?

In Excel worksheet, how could you extract the date from text strings as following screenshot shown? This article, I will talk about a useful formula to solve it.

Extract date from text strings with array formula in worksheet

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Extract date from text strings with array formula in worksheet

To extract only date from a list of text strings, the following array formula can help you, please do as this:

1. Enter this formula:

=MID(A2,MIN(IFERROR(FIND({0,1,2,3,4,5,6,7,8,9},A2,1),LEN(A2)+1)),LOOKUP(1,0/MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1),ROW(INDIRECT("1:"&LEN(A2)))) + 1 - MIN(IFERROR(FIND({0,1,2,3,4,5,6,7,8,9},A2,1),LEN(A2)+1))) into a blank cell where you want to get the result, and then press Ctrl + Shift + Enter keys together, and only the date is extracted as following screenshot shown:

2. Then select the formula cell, and drag the fill handle down to the cells you want to apply this formula, and you will get the results as you need, see screenshot:

Notes:

1. In the above formula, A2 is the cell which contains the date you want to extract;

2. If the cell contains other numbers, this formula will not work correctly；

3. The formula cannot correctly extract date while there is more than one date in the text string.

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  • To post as a guest, your comment is unpublished.
    Anett · 7 months ago
    Hi, Help me please! How about if my text is "Date and time of submission:23-Jun-2017 12:34:58 AM PDT. What kind of formula can i use ?
  • To post as a guest, your comment is unpublished.
    Nancy · 10 months ago
    how about if my text is "Date and time of submission: September 16, 2018 at 11:26:00 PM PDT"? What kind of formula can i use ?
  • To post as a guest, your comment is unpublished.
    Tak · 1 years ago
    I'm using Excel 2003, so I believe the IFERROR does not exist, and I found this quoted on the web to be the equivalent:

    IFERROR(A1,"") = IF(ISERROR(A1),"")

    So I'm trying this:

    =MID(A2,MIN(IF(ISERROR(FIND({0,1,2,3,4,5,6,7,8,9},A2,1)),LEN(A2)+1)),LOOKUP(1,0/MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1),ROW(INDIRECT("1:"&LEN(A2)))) + 1 - MIN(IF(ISERROR(FIND({0,1,2,3,4,5,6,7,8,9},A2,1)),LEN(A2)+1)))

    - I did press CTRL+SHIFT+ENTER the actual forumla in excel shows it in {}

    Using this formula, I just get a blank result

    Can check and let me know where I’ve gone wrong... Or is it not possible in Excel 2003

    Thank you
    • To post as a guest, your comment is unpublished.
      Tak · 1 years ago
      Actually my data to extract is in the format:

      Data valid for 14 December 2018

      So I need to extract the "14 December 2018" and not the usual
      xx/xx/xx
      • To post as a guest, your comment is unpublished.
        Tak · 1 years ago
        This seemsto for work me(Excel 2003)

        =DATEVALUE(MID(A2,MIN(SEARCH({0,1,2,3,4,5,6,7,8,9},A2&"0123456789")),17))

        : A2 contains the data to extract

        : it finds the first numerical value, then translates restas date

        Works for data in this format : Data valid for 14 December 2018
        • To post as a guest, your comment is unpublished.
          sree · 1 months ago
          Hi Tak,
          Its working perfectly. But why "17" at the end? kindly assist.
          • To post as a guest, your comment is unpublished.
            Tak · 1 months ago
            Looking at the "mid" function" it's = number of characters...

            So the longest it will be = "dd september yyyy" = 17 characters

            2 = date
            9 = month
            4 = year
            2 = spaces

            Maybe I should have said the data is : "25 September 2018"

            So 17 should cover for all the months of the year :)
  • To post as a guest, your comment is unpublished.
    SHWETA · 1 years ago
    PLEASE HELP ME EXTRACT DATE FROM THE STATEMENTS LIKE "PLEASE DELIVER BY Fri,01 January ,2016"
  • To post as a guest, your comment is unpublished.
    chathuka perera · 1 years ago
    Can someone help me find a string to extract the date in this format please yyyy-mm-dd
    "2018-03-24T01:42:26-07:00"



    Thanks much in advance
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